ln((x+9)/(x-9))^1/7

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Solution for ln((x+9)/(x-9))^1/7 equation:


D( x )

(x+9)/(x-9) <= 0

x-9 = 0

(x+9)/(x-9) <= 0

(x+9)/(x-9) <= 0

( x+9 )

x+9 <= 0 // - 9

x <= -9

( x-9 )

x-9 <= 0 // + 9

x <= 9

(-oo:-9)(-9:9)(9:+oo)x+9-++x-9--+

x-9 = 0

x-9 = 0

x-9 = 0 // + 9

x = 9

x in (-oo:-9) U (9:+oo)

((ln((x+9)/(x-9)))^1)/7 = 0

ln((x+9)/(x-9))/7 = 0

1/7*ln((x+9)/(x-9)) = 0 // : 1/7

ln((x+9)/(x-9)) = 0

ln((x+9)/(x-9)) = ln(e^0)

(x+9)/(x-9) = e^0

(x+9)/(x-9)-e^0 = 0

(x+9)/(x-9)-1 = 0

(x+9)/(x-9)+(-1*(x-9))/(x-9) = 0

x-1*(x-9)+9 = 0

18 = 0

18/(x-9) = 0

18/(x-9) = 0 // * x-9

18 = 0

x belongs to the empty set

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